求助syc解决一道题，挺着急的。@syc

535638819zsm

美国同学发来的题，我翻译了一下。应该就是按翻译上说的，给出了函数的格式，实现把int值存储到指向由int指向的位置的4个字节位置。
int is_little_endian(void (*store)(int*,int)) {
  int x;
  // The cast below is to have an unsigned char pointer pointing
  // to the first byte of int variable x. You can use it
  // in your code to observe x one byte at a time.
  unsigned char *byte_ptr = (unsigned char*)(&x);
  // This is how you call store function.
  // After the function call, value 1 is stored
  // in the four bytes x is referring to in some order.
  // One of the four bytes will have the value 1, and the
  // other three bytes will have the value 0.
  // You can call store function with any value that you think
  // will help you solve the problem.
  // Refer to code in Figure 2.4 on page 45 of the textbook
  // to see how you retrieve one byte at a time.
  store(&x, 1);  

  // Replace 0 with a proper value that will be 0 when store
  // is not little endian and 1 when store is little endian.
  return 0;
}
@Syc

Syc

这个问题就是用他描述的文本意思来实现检测当前是大端还是小端的问题吧？
看看这篇文章，马上就能解决楼主的问题了：

判断计算机是大端还是小端
https://blog.csdn.net/lwfcgz/article/details/50476051

535638819zsm

Syc 发表于 2018-8-30 13:59
这个问题就是用他描述的文本意思来实现检测当前是大端还是小端的问题吧？
看看这篇文章，马上就能解决楼主 ...

看我倒是看懂了，但是不会按照他给的这种函数方式来写......能不能帮忙写一下呢....